$ABCD$ forms a parallelogram. $N$ lies on $BD$ so that $BN : ND = 4 : 1$. $AB = s$ and $AD = t$. The sketch is not drawn to scale.
(a)[1]
$\overrightarrow{BD}$.
(b)[3]
$\overrightarrow{CN}$.
Worked solution & mark scheme
This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: “$-s+t$” …
- Full mark scheme, point by point
- Step-by-step worked solution
- Write your answer & get it marked instantly by AI