Mathematics 0580 · IGCSE · Surds

Surds — practice question

(a)[2]

Simplify the expression $\sqrt{27} + \sqrt{12}$.

(b)[2]

Given $\frac{40\sqrt{8}}{5\sqrt{2}} = k$, where $k$ is an integer, find the integer value of $k$.

(c)[2]

Rationalise the denominator in $\frac{1}{3 - \sqrt{5}}$.

Worked solution & mark scheme

This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: The answer is $5\sqrt{3}$.

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