(a)[2]
Simplify the expression $\sqrt{27} + \sqrt{12}$.
(b)[2]
Given $\frac{40\sqrt{8}}{5\sqrt{2}} = k$, where $k$ is an integer, find the integer value of $k$.
(c)[2]
Rationalise the denominator in $\frac{1}{3 - \sqrt{5}}$.
Mathematics 0580 · IGCSE · Surds
Simplify the expression $\sqrt{27} + \sqrt{12}$.
Given $\frac{40\sqrt{8}}{5\sqrt{2}} = k$, where $k$ is an integer, find the integer value of $k$.
Rationalise the denominator in $\frac{1}{3 - \sqrt{5}}$.