A triangle $ABC$ is drawn, with angle $C$ equal to $65^{\circ}$. The perpendicular distance from $B$ to $AC$ is $12.8\text{ cm}$.
(main)[3]
Calculate the length of $BC$.
Worked solution & mark scheme
This 3-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Correct application of $\sin 65^\circ = \frac{12.8}{BC}$” …