$y$ varies inversely with $(x+1)^{2}$. $y = 50$ when $x = 0.2$.
(a)[2]
Express $y$ in terms of $x$.
(b)[1]
Determine the value of $y$ when $x = 0.5$.
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This 3-mark question has a full step-by-step worked solution and mark scheme. One marking point: “$y =\frac{k}{(x+1)^2}$” …
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