Mathematics 0580 · IGCSE · Proportion

Proportion — practice question

Between two magnets, the attractive force $F$ Newtons varies inversely with the square of the distance $d$, cm, separating the magnets. If $d = 1.5$, then $F = 48$.
(a)[2]

Find an expression for $F$ as a function of $d$.

(b)[1]

If the separation between the two magnets is doubled, the new force becomes $n$ times the original force. Work out the value of $n$.

Worked solution & mark scheme

This 3-mark question has a full step-by-step worked solution and mark scheme. One marking point: The result is $F=\frac{108}{d^2}$.

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