Mathematics 0580 · IGCSE · Non-right-angled triangles

Non-right-angled triangles — practice question

The figure places ships A, B and C on a map. $AC = 17.6$ km, $BC = 12.8$ km and $\angle BAC = 25^{\circ}$. The bearing of C from B is $112^{\circ}$, while $\angle ABC$ is obtuse. Diagram NOT TO SCALE.
(main)[5]

Calculate the bearing of B from A, in degrees.

Worked solution & mark scheme

This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: “$\sin(\angle ABC)=\dfrac{17.6\sin25}{12.8}$” …

  • Full mark scheme, point by point
  • Step-by-step worked solution
  • Write your answer & get it marked instantly by AI