Mathematics 0580 · IGCSE · Non-right-angled triangles

Non-right-angled triangles — practice question

For this question, every measurement is in centimetres. The diagram depicts a triangle with sides $r+2$ and $r+5$ and a $30^{\circ}$ angle, together with a square of side $r+1$ (NOT TO SCALE). The triangle's area is the same as the square's area.
(a)[4]

Show that the result is $3r^2+r-6=0$.

(b)[3]

Solve the equation $3r^2+r-6=0$. Give your answer to 2 decimal places, and show all your working.

(c)[2]

Find the square's perimeter.

Worked solution & mark scheme

This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: Area equation: $\dfrac12(r+5)(r+2)\sin30=(r+1)^2$

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