The diagram represents trapezium $ABCD$ (not drawn to scale), with $DC$ parallel to $AB$. Here, $DC = 6.4\,\text{cm}$, $DB = 10.9\,\text{cm}$, angle $CDB = 38^{\circ}$ and angle $DAB = 45^{\circ}$.
(b(i))[1]
Find angle $ADB$.
(c)[3]
Calculate the area of the trapezium.
Worked solution & mark scheme
This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: “$\sqrt{6.4^2+10.9^2-2\times6.4\times10.9\cos38}$” …
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