Mathematics 0580 · IGCSE · Non-right-angled triangles

Non-right-angled triangles — practice question

The diagram represents trapezium $ABCD$ (not drawn to scale), with $DC$ parallel to $AB$. Here, $DC = 6.4\,\text{cm}$, $DB = 10.9\,\text{cm}$, angle $CDB = 38^{\circ}$ and angle $DAB = 45^{\circ}$.
(a)[3]

Find $CB$.

(b(i))[1]

Find angle $ADB$.

(b(ii))[3]

Find $AB$.

(c)[3]

Calculate the area of the trapezium.

Worked solution & mark scheme

This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: $\sqrt{6.4^2+10.9^2-2\times6.4\times10.9\cos38}$

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