Mathematics 0580 · IGCSE · Non-right-angled triangles

Non-right-angled triangles — practice question

The diagram depicts quadrilateral $ABCD$, which is formed by triangles $ABD$ and $BCD$.
(a)[3]

Show that $BD = 16.9$ m, accurate to 1 decimal place.

(b)[4]

Calculate the angle $CBD$.

(c)[3]

Determine the area of quadrilateral $ABCD$.

(d)[3]

Find the shortest distance from $B$ to $AD$.

Worked solution & mark scheme

This 13-mark question has a full step-by-step worked solution and mark scheme. One marking point: $\sqrt{16^2+19^2-2\times16\times19\cos57}$​

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