The figure shows a triangle in which $CB = 8.15\text{ m}$, the angle at $A$ is $110^\circ$, and the angle at $B$ is $30^\circ$. It is labelled NOT TO SCALE.
(main)[3]
Calculate the value of $AC$.
Worked solution & mark scheme
This 3-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Sine-rule form: $\frac{8.15\sin30}{\sin110}$” …