Mathematics 0580 · IGCSE · Non-right-angled triangles

Non-right-angled triangles — practice question

The sketch features the two ports $L$ and $P$ together with a buoy, $M$. From $P$, the bearing to $L$ is $201^\circ$ and $LP = 248$ km. From $P$, the bearing to $M$ is $127^\circ$. Angle $PML = 42^\circ$.
(a)[4]

Apply the sine rule to calculate $LM$.

(b(i))[3]

Calculate the shortest distance from $M$ to $LP$.

(b(ii))[3]

Calculate the time on the following day when the ship arrives at $P$.

Worked solution & mark scheme

This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: The answer is $356$.

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