The table lists several values for $y = x^3 + 4x^2 - 4$.
Table: $x = -4.5, -4, -3, -2, -1, 0, 1, 1.5$ together with corresponding $y = -14.1, [blank], 5, 4, [blank], -4, 1, 8.4$.
(b)[4]
Using the grid, Draw the graph of $y = x^3 + 4x^2 - 4$ for $-4.5 \leq x \leq 1.5$.
(c(i))[1]
Draw the tangent to the graph at the point $(1,1)$.
(c(ii))[2]
Use your tangent to estimate the gradient of the curve at the point $(1,1)$.
(d)[4]
Use a suitable straight line drawn on the grid to solve the equation $x^3 + 4x^2 - x - 6 = 0$.
Worked solution & mark scheme
This 13-mark question has a full step-by-step worked solution and mark scheme. One marking point: “$x=-4$ and $x=-1$ are both correct.” …
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