The table gives some values of $y=x^2-\dfrac{3}{2x}$, with $x\neq0$, rounded to 1 decimal place.
(a(i))[3]
Fill in the table.
(a(ii))[5]
On the grid, sketch the graph of $y=x^2-\dfrac{3}{2x}$ for $-3\le x\le -0.2$ and $0.2\le x\le 3$.
(b)[4]
Using an appropriate straight line on the grid, solve the equation $x^2-\dfrac{3}{2x}=\dfrac{24}{5}-2x$.
(c)[4]
The roots are also the roots of an equation of the form $ax^3+bx^2+cx-15=0$. Find the values of $a$, $b$ and $c$.
Worked solution & mark scheme
This 16-mark question has a full step-by-step worked solution and mark scheme. One marking point: “$x = 9.5,\;4.8,\;8.5$” …
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