The table lists some values of $y = x^3 - 3x + 2$. The x‑values shown are -2, -1.5, -1, -0.5, 0, 0.5, 1, 1.5, 2.
(a)[4]
Complete the values in the table.
(b)[4]
On the grid, sketch the graph of $y = x^3 - 3x + 2$ for $-2 \leq x \leq 2$.
(c)[3]
By drawing an appropriate line, solve $x^3 - 3x + 2 = x + 1$ for $-2 \leq x \leq 2$.
(d)[3]
By drawing a suitable tangent, estimate the gradient of the curve at the point where $x = -1.5$.
Worked solution & mark scheme
This 14-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Correct values are $0, 4, 0.625, 0.875$” …
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