Mathematics 0580 · IGCSE · Differentiation

Differentiation — practice question

The table gives some values for $y = x^3 - 3x - 1$.
(a)[2]

Complete the values table.

(b)[4]

Using the interval $-3 \le x \le 3$, draw the graph of $y = x^3 - 3x - 1$.

(c(i))[1]

Draw this tangent on the grid.

(c(ii))[1]

Find the coordinates of the point at which the tangent meets your graph.

(c(iii))[3]

Find the equation of the tangent, and give your answer in the form $y = mx + c$.

(d)[4]

By drawing an appropriate straight line on the grid, solve the equation $x^3 - 6x - 3 = 0$.

Worked solution & mark scheme

This 15-mark question has a full step-by-step worked solution and mark scheme. One marking point: The value is $-3$.

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