Three regular polygons $A$, $B$ and $C$ are joined at one point. Their interior angles are in the ratio $a : b : c = 3 : 4 : 5$. The diagram labels the angles at the shared point as $a^\circ$, $b^\circ$ and $c^\circ$.
(main)[5]
Show that polygon $C$ has twice as many sides as polygon $B$.
Worked solution & mark scheme
This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Accurate interior-angle relation $\frac{180(n-2)}{n}$” …