The matrices are $A = \begin{pmatrix}2 & 7\\ 1 & 3\end{pmatrix}$ and $B = \begin{pmatrix}3 & 4\\ 0 & 1\end{pmatrix}$.
(a)[2]
Calculate the product $AB$.
(b)[2]
Find the inverse matrix $A^{-1}$ of $A$.
Worked solution & mark scheme
This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: “So, $AB=\begin{pmatrix}6 & 15 \\ 3 & 7\end{pmatrix}$.” …