Chemistry 0620 · IGCSE · The mole and the Avogadro constant

The mole and the Avogadro constant — practice question

$4.55\,\text{g}$ of zinc is made to react with $50\,\text{cm}^3$ of $2.25\,\text{mol dm}^{-3}$ dilute hydrochloric acid. The equation for the reaction is shown. $\text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2$ What volume of hydrogen gas is formed at room temperature and pressure?

  • A$1.35\,\text{dm}^3$
  • B$1.67\,\text{dm}^3$
  • C$2.70\,\text{dm}^3$
  • D$3.34\,\text{dm}^3$

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