Sodium hydroxide is reacted with sulfuric acid. The reaction equation is given below. $2\text{NaOH} + \text{H}_2\text{SO}_4 \rightarrow \text{Na}_2\text{SO}_4 + 2\text{H}_2\text{O}$ What volume of $0.4\,\text{mol dm}^{-3}$ sodium hydroxide will react with $50.0\,\text{cm}^3$ of $0.1\,\text{mol dm}^{-3}$ sulfuric acid?
- A$12.5\,\text{cm}^3$
- B$25.0\,\text{cm}^3$
- C$50.0\,\text{cm}^3$
- D$100.0\,\text{cm}^3$