On heating, copper(II) oxide, $\text{CuO}$, reacts with ammonia, $\text{NH}_3$. $3\text{CuO} + 2\text{NH}_3 \rightarrow 3\text{Cu} + \text{N}_2 + 3\text{H}_2\text{O}$ $8.5\,\text{g}$ of ammonia reacts with an excess of copper(II) oxide to produce $26.4\,\text{g}$ of copper. Calculate the percentage yield of copper in this reaction.
- A$27.5\%$
- B$32.2\%$
- C$55.0\%$
- D$82.5\%$