An ester, $\text{C}_4\text{H}_8\text{O}_2$, is produced when 0.06 mol of ethanol, $\text{C}_2\text{H}_6\text{O}$, reacts with 0.05 mol of ethanoic acid, $\text{C}_2\text{H}_4\text{O}_2$. $\text{C}_2\text{H}_6\text{O} + \text{C}_2\text{H}_4\text{O}_2 \rightarrow \text{C}_4\text{H}_8\text{O}_2 + \text{H}_2\text{O}$ The amount of ester formed was 0.0375 mol. What are the percentage yield and the $M_r$ of the ester?
- Apercentage yield = 62.5; $M_r = 48$
- Bpercentage yield = 75.0; $M_r = 48$
- Cpercentage yield = 62.5; $M_r = 88$
- Dpercentage yield = 75.0; $M_r = 88$