The reaction equation for calcium carbonate reacting with hydrochloric acid is given below. $\text{CaCO}_3\text{(s)} + 2\text{HCl(aq)} \rightarrow \text{CaCl}_2\text{(aq)} + \text{H}_2\text{O(l)} + \text{CO}_2\text{(g)}$ What number of moles of calcium carbonate would produce $24\,\text{cm}^3$ of carbon dioxide if the acid is in excess?
- A$1\,\text{mol}$
- B$0.1\,\text{mol}$
- C$0.01\,\text{mol}$
- D$0.001\,\text{mol}$