Chemistry 0620 · IGCSE · Reversible reactions and equilibrium

Reversible reactions and equilibrium — practice question

The displayed symbol equation for the industrial manufacture of ammonia is: $\text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g) \quad \Delta H = -90\,\text{kJ/mol}$
(a)[1]

Name the industrial process illustrated.

(b)[1]

State what $\Delta H$ stands for.

(c)[3]

State the usual conditions and name the catalyst used in the industrial manufacture of ammonia.

(d)[2]

State two ways of increasing the rate of this reaction.

(e)[3]

Use the bond energies listed in Table 3.1 together with $\Delta H$ to find the bond energy of an N-H bond, in kJ/mol. Follow the steps below.

(f(i))[1]

Complete the symbol equation for the laboratory preparation of ammonia: $\text{CaO} + 2\text{NH}_4\text{Cl} \rightarrow \text{CaCl}_2 + [BLANK] + 2\text{NH}_3$.

(f(ii))[1]

Name $\text{NH}_4\text{Cl}$.

(f(iii))[3]

Calculate the volume of ammonia, $\text{NH}_3$, at room temperature and pressure that is produced when 1.12 g of CaO is heated with excess $\text{NH}_4\text{Cl}$.

Worked solution & mark scheme

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