Chemistry 0620 · IGCSE · Reversible reactions and equilibrium

Reversible reactions and equilibrium — practice question

Sulfur dioxide reacts with excess oxygen to produce sulfur trioxide. $\text{2SO}_2(g) + \text{O}_2(g) \rightleftharpoons \text{2SO}_3(g)$
(a)[1]

What does the symbol $\rightleftharpoons$ mean?

(b)[1]

Would you describe this reaction as exothermic or endothermic? Support your choice with a reason.

(c(i))[1]

Describe how the percentage yield of sulfur trioxide varies with temperature.

(c(ii))[1]

Find the percentage yield of sulfur trioxide at $500\,^{\circ}\text{C}$.

(d)[2]

Describe a test for sulfur dioxide. Give both the test and the result.

(e)[1]

Give one use of sulfur dioxide.

(f)[2]

Which substance is reduced in this reaction? Explain your response.

(g)[1]

Complete the chemical equation for this reaction. $\text{H}_2\text{SO}_3 + 2\text{H}_2\text{S} \rightarrow .....\text{H}_2\text{O} + 3\text{S}$

Worked solution & mark scheme

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