Chemistry 0620 · IGCSE · Rate of reaction

Rate of reaction — practice question

Dilute hydrochloric acid reacts with copper(II) oxide. $\text{CuO}(s) + 2\text{HCl}(aq) \rightarrow \text{CuCl}_2(aq) + \text{H}_2\text{O}(l)$ A mass of 6.00 g of copper(II) oxide was added to 50.0 $\text{cm}^3$ of 1.00 $\text{mol dm}^{-3}$ hydrochloric acid. Copper(II) oxide was in excess.
(a(i))[2]

Using collisions, explain why a higher concentration of hydrochloric acid makes the reaction faster.

(a(ii))[2]

Using collisions, explain why heating the hydrochloric acid makes the reaction faster.

(b(i))[2]

Calculate the amount, in moles, of copper(II) oxide added to the hydrochloric acid.

(b(ii))[1]

Calculate the amount, in moles, of hydrochloric acid used.

(b(iii))[2]

Calculate the mass of copper(II) oxide that remained unreacted.

(c)[2]

Calculate the empirical formula for the crystals.

Worked solution & mark scheme

This 11-mark question has a full step-by-step worked solution and mark scheme. One marking point: “A larger number of acid particles in the same volume” …

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