Ethyl methanoate, $\text{HCOOC}_2\text{H}_5$, is combusted in an excess of oxygen, forming carbon dioxide and water. The equation is given below. $2\text{HCOOC}_2\text{H}_5 + x\text{O}_2 \rightarrow 6\text{CO}_2 + 6\text{H}_2\text{O}$ Determine the value of $x$?
- A$2$
- B$7$
- C$9$
- D$18$