Methane is burned in excess oxygen. The equation is given as: $\text{CH}_4(g) + 2\text{O}_2(g) \rightarrow \text{CO}_2(g) + 2\text{H}_2\text{O}(g)$. Bond energies are shown. What is the energy change for this reaction?
- A$(4 \times 410 + 2 \times 496) - (2 \times 805 + 4 \times 460)$
- B$(2 \times 805 + 4 \times 460) - (4 \times 410 + 2 \times 496)$
- C$(410 + 2 \times 496) - (805 + 2 \times 460)$
- D$(410 + 496) - (805 + 460)$