Dilute sulfuric acid undergoes electrolysis with inert electrodes. What are the ionic half-equations for the reactions occurring at each electrode?
- Apositive electrode: $2\text{H}^+ + 2e^- \rightarrow \text{H}_2$; negative electrode: $4\text{OH}^- \rightarrow 2\text{H}_2\text{O} + \text{O}_2 + 4e^-$
- Bpositive electrode: $2\text{H}^+ + 2e^- \rightarrow \text{H}_2$; negative electrode: $4\text{OH}^- + 4\text{H}^+ \rightarrow 4\text{H}_2\text{O}$
- Cpositive electrode: $4\text{OH}^- \rightarrow 2\text{H}_2\text{O} + \text{O}_2 + 4e^-$; negative electrode: $2\text{H}^+ + 2e^- \rightarrow \text{H}_2$
- Dpositive electrode: $4\text{OH}^- + 4\text{H}^+ \rightarrow 4\text{H}_2\text{O}$; negative electrode: $2\text{H}^+ + 2e^- \rightarrow \text{H}_2$