The reaction equation for dilute ethanoic acid with aqueous lithium hydroxide is given here: $\text{CH}_3\text{COOH} + \text{LiOH} \rightarrow \text{CH}_3\text{COOLi} + \text{H}_2\text{O}$. During an experiment, $20.0\,\text{cm}^3$ of $0.050\,\text{mol dm}^{-3}$ aqueous lithium hydroxide is completely neutralised by $12.5\,\text{cm}^3$ of dilute ethanoic acid. Which statement is correct?
- AThe amount of lithium hydroxide is equal to $0.050 \times \frac{1000}{20}$ mol.
- BThe amount of ethanoic acid reacted is $0.0010$ mol.
- CThe concentration of the dilute ethanoic acid is $0.16\,\text{mol dm}^{-3}$.
- DThe volume of aqueous lithium hydroxide used is $0.20\,\text{dm}^3$.