Chemistry 0620 · IGCSE · Acid–base titrations

Acid–base titrations — practice question

Hydrochloric acid, HCl(aq), when dilute, reacts with aqueous sodium carbonate, Na_2CO_3(aq). The reaction is represented by the equation below. 2HCl + Na_2CO_3 → 2NaCl + CO_2 + H_2O
(a)[3]

Calculate the concentration of the Na_2CO_3(aq), in mol/dm^3, by carrying out these steps: Calculate how many moles of HCl were used in the titration. Calculate how many moles of Na_2CO_3 were present in the 25.0 cm^3 sample of Na_2CO_3(aq). Calculate the concentration of the Na_2CO_3(aq) in mol/dm^3.

(b)[1]

How many moles of CO_2 does this represent?

(c(i))[1]

Calculate the concentration of HBr(aq), in g/dm^3.

(c(ii))[2]

Explain why concentrated HBr(aq) is able to conduct electricity.

(c(iii))[1]

Explain why this is so.

(c(iv))[1]

Predict the product at the anode when concentrated HBr(aq) undergoes electrolysis.

(c(v))[2]

Write the ionic half-equation for the process at the cathode.

Worked solution & mark scheme

This 11-mark question has a full step-by-step worked solution and mark scheme. One marking point: M1: n(HCl) = 0.0036

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