The diagram represents a uniform bar with mass $M$ and length $L$ supported on a pivot positioned a distance $x$ from end X. A mass $m$ is put on the bar at a distance $y$ from the pivot so that the bar remains in equilibrium. What expression gives $y$?
- A$\frac{xM}{m}$
- B$\frac{M}{m}(L-x)$
- C$\frac{M}{2m}(L-2x)$
- D$\frac{1}{m}(Lm-xM)$