A beam of uniform density has a mass of $1.4\,\text{kg}$ and is supported on a pivot at P, as shown. Its length is $0.60\,\text{m}$, and P is located $0.20\,\text{m}$ from one end. Masses of $3.0\,\text{kg}$ and $6.0\,\text{kg}$ are hung at distances of $0.35\,\text{m}$ and $0.15\,\text{m}$ from the pivot, as shown. Calculate the torque that has to be applied to the beam so that it remains in equilibrium?
- A$0.010\,\text{N m}$
- B$0.10\,\text{N m}$
- C$0.29\,\text{N m}$
- D$2.8\,\text{N m}$