Physics 9702 · AS & A Level · Turning effects of forces

Turning effects of forces — practice question

(a)[2]

Define the centre of gravity.

(b)

A uniform rod AB is fixed to a vertical wall at A. A string holds the rod horizontally by being attached at B and at point C, as shown in Fig. 3.1. The angle between the rod and the string at B is $50^{\circ}$. The rod has length $1.2\,\text{m}$ and weight $8.5\,\text{N}$. An object O of mass $M$ is suspended from the rod at B. The tension $T$ in the string is $30\,\text{N}$.

(b(i))[1]

Use the resolution of forces to find the vertical component of $T$.

(b(ii))[1]

State the principle of moments in equilibrium.

(b(iii))[3]

Use the principle of moments and take moments about A to show that the weight of object O is $19\,\text{N}$.

(b(iv))[1]

Hence determine the mass $M$ for object O.

(c)[2]

Use the concept of equilibrium to explain why a force has to act on the rod at A.

Worked solution & mark scheme

This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: Centre of mass defined as the point where weight is regarded as acting.

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