A uniform beam of mass $1.4\,\text{kg}$ is supported at the pivot $P$ as shown. The beam is $0.60\,\text{m}$ long, and $P$ lies $0.20\,\text{m}$ from one end. Masses of $3.0\,\text{kg}$ and $6.0\,\text{kg}$ hang from the beam at distances of $0.35\,\text{m}$ and $0.15\,\text{m}$ from the pivot, as shown. What torque is needed to be applied to keep the beam in equilibrium?
- A$0.010\,\text{N m}$
- B$0.10\,\text{N m}$
- C$0.29\,\text{N m}$
- D$2.8\,\text{N m}$