A cube WXYZ with edge length $2.0\,\text{cm}$ and mass $24.0\,\text{g}$ is placed on a metre rule of negligible mass. The cube’s geometrical centre is directly above the $70.0\,\text{cm}$ mark on the scale of the rule. Because the cube is not of uniform density, its centre of gravity does not coincide with its geometrical centre. The cube’s centre of gravity lies in the plane of the diagram. The rule is supported by a pivot at the $50.0\,\text{cm}$ mark. A mass of $23.4\,\text{g}$ is positioned vertically above the $30.0\,\text{cm}$ mark. The rule remains horizontal and is in equilibrium. What can be inferred about the location of the cube’s centre of gravity?
- AIt must be somewhere along a horizontal line that is $0.5\,\text{cm}$ from line WX.
- BIt must be somewhere along a horizontal line that is $0.5\,\text{cm}$ from line YZ.
- CIt must be somewhere along a vertical line that is $0.5\,\text{cm}$ from line WY.
- DIt must be somewhere along a vertical line that is $0.5\,\text{cm}$ from line XZ.