Wires P and Q are each made from the same metal and are suspended vertically from a steel support beam. Wire Q is half the length of wire P and has twice the diameter of wire P. The same masses are hung from the lower end of each wire. As the masses stretch the wires, both wires obey Hooke’s law. What is the value of $\frac{\text{extension of wire P}}{\text{extension of wire Q}}$?
- A$\frac{8}{1}$
- B$\frac{4}{1}$
- C$\frac{1}{1}$
- D$\frac{1}{2}$