An object of weight $10\,\text{kN}$ is supported equally by four solid steel rods, each with length $2.0\,\text{m}$ and cross-sectional area $250\,\text{mm}^2$. As a result of the object's weight, the rods shorten by $0.10\,\text{mm}$. Assume the rods follow Hooke’s law. What is the Young modulus of steel?
- A$2.0 \times 10^8\,\text{N m}^{-2}$
- B$2.0 \times 10^{11}\,\text{N m}^{-2}$
- C$8.0 \times 10^8\,\text{N m}^{-2}$
- D$8.0 \times 10^{11}\,\text{N m}^{-2}$