State the two forces acting on the tube immediately after release.
State and explain the direction of the resultant force on the tube immediately after release.
The acceleration $a$ of the tube is given by the expression $a = -\left(\frac{A\rho g}{M}\right)x$, where $x$ is the vertical displacement of the tube from its equilibrium position. Use the expression to explain why the tube performs simple harmonic oscillations in the liquid.
A tube with cross-sectional area $A$ equal to $4.5\,\text{cm}^2$ and total mass $M$ equal to $0.17\,\text{kg}$ oscillates with period $1.3\,\text{s}$. Determine the angular frequency $\omega$ of the oscillations.
Use your answer in (i) and the expression in (b) to find the density $\rho$ of the liquid that the tube is floating in.