A particle moves with velocity $V$, making an angle $\theta$ with the horizontal. Its velocity components are $V_v$ vertically upwards and $V_h$ horizontally to the right, as illustrated. What expressions give the magnitude of $V$ and the angle $\theta$?
- Amagnitude of $V$: $\sqrt{V_v^2 + V_h^2}$, $\theta = \tan^{-1}\!\left(\frac{V_h}{V_v}\right)$
- Bmagnitude of $V$: $\sqrt{V_v^2 + V_h^2}$, $\theta = \tan^{-1}\!\left(\frac{V_v}{V_h}\right)$
- Cmagnitude of $V$: $\sqrt{V_v^2 - V_h^2}$, $\theta = \tan^{-1}\!\left(\frac{V_h}{V_v}\right)$
- Dmagnitude of $V$: $\sqrt{V_v^2 - V_h^2}$, $\theta = \tan^{-1}\!\left(\frac{V_v}{V_h}\right)$