A light beam has power $P$ and a cross-sectional area of $A$. The wave amplitude in the beam is $X$. The beam is then altered so that its frequency stays the same, but its amplitude becomes $4X$ and its cross-sectional area decreases to $\frac{A}{3}$. What is the power of this new beam?
- A$1.3P$
- B$5.3P$
- C$12P$
- D$48P$