For the circuit diagram shown, XY is a length $L$ of uniform resistance wire. A potential difference is applied across XY. $R_1$ and $R_2$ are unknown resistors. J is a sliding contact that connects the junction of $R_1$ and $R_2$ to positions on XY through a lamp S. J is shifted along XY until the lamp is not lit. This position is a distance $x$ from X. The potential difference across $R_1$ is $V_1$ and the potential difference across $R_2$ is $V_2$. What is the value of the ratio $\dfrac{V_1}{V_2}$?
- A$\dfrac{L}{x}$
- B$\dfrac{x}{L}$
- C$\dfrac{L - x}{x}$
- D$\dfrac{x}{L - x}$