In the circuit diagram shown, XY is a length $L$ of uniform resistance wire. $R_1$ and $R_2$ are unknown resistors. J is a sliding contact that connects the junction of $R_1$ and $R_2$ to positions on XY through a small signal lamp S. To find the ratio $\frac{V_1}{V_2}$ of the potential differences across $R_1$ and $R_2$, a point is located on XY where the lamp is not lit. This point lies a distance $x$ from X. What is the value of the ratio $\frac{V_1}{V_2}$?
- A$\frac{L}{x}$
- B$\frac{x}{L}$
- C$\frac{L - x}{x}$
- D$\frac{x}{L - x}$