The potential difference (p.d.) across a fixed resistor is $V$. The resistor dissipates power of $5.0\,\text{W}$. The p.d. across the resistor then takes a different value. At this new p.d., the energy transferred to the resistor during $2.25\,\text{s}$ is $45.0\,\text{J}$. Determine the new p.d. across the resistor?
- A$\frac{1}{2}V$
- B$2V$
- C$3V$
- D$4V$