Physics 9702 · AS & A Level · Potential difference and power

Potential difference and power — practice question

(a)[1]

State the definition of electric field strength.

(b(i))[2]

A proton starts from rest on the positive plate. In the uniform electric field it takes $1.5 \times 10^{-7}\,\text{s}$ to arrive at the negative plate. Show that the proton’s acceleration is $4.0 \times 10^{12}\,\text{m s}^{-2}$.

(b(ii))[1]

Calculate the electric force acting on the proton.

(b(iii).1)[2]

Use your result from (ii) to find the electric field strength.

(b(iii).2)[2]

Use your result from (ii) to find the potential difference $V$ across the plates.

(c)[2]

An $\alpha$ particle is now accelerated by the electric field between the two metal plates in (b). Calculate the ratio $\dfrac{\text{acceleration of } \alpha \text{ particle}}{\text{acceleration of proton}}$.

Worked solution & mark scheme

This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: Electric field strength is the force per unit positive charge

  • Full mark scheme, point by point
  • Step-by-step worked solution
  • Write your answer & get it marked instantly by AI