A charged particle is placed in the electric field between two horizontal metal plates that are connected to a battery, as illustrated. The electric field exerts a force $F$ on the particle. The gap between the plates is increased so that it is twice as large. What is the new force on the particle?
- A$\frac{F}{4}$
- B$\frac{F}{2}$
- C$F$
- D$2F$