A brick with a weight of $20\,\text{N}$ is placed on an inclined plane. The component of the brick’s weight acting parallel to the plane is $10\,\text{N}$. In addition, a frictional force of $4\,\text{N}$ acts on the brick. Calculate the acceleration of the brick down the plane. Take the acceleration of free fall $g$ to be equal to $10\,\text{m s}^{-2}$.
- A$0.3\,\text{m s}^{-2}$
- B$0.8\,\text{m s}^{-2}$
- C$3.0\,\text{m s}^{-2}$
- D$8.0\,\text{m s}^{-2}$