A car with mass $500\,\text{kg}$ is stationary at point $X$ on a slope, as illustrated. The car’s brakes are then released, and with the engine turned off the car rolls down the slope. By point $Y$, the car has descended through a vertical height of $30\,\text{m}$ and is travelling at a speed of $11\,\text{m s}^{-1}$. What is the energy dissipated by frictional forces as the car moves from $X$ to $Y$?
- A$3.0 \times 10^{4}\,\text{J}$
- B$1.2 \times 10^{5}\,\text{J}$
- C$1.5 \times 10^{5}\,\text{J}$
- D$1.8 \times 10^{5}\,\text{J}$