Explain why the particle moves along an arc of a circle in the magnetic field.
The radius of the arc in (a) is $r$. Show that the particle’s ratio $\frac{q}{m}$ is given by $\frac{q}{m} = \frac{v}{Br}$.
Use these values to find the ratio $\frac{q}{m}$. The particle’s initial speed $v$ is $2.0 \times 10^7\,\text{m s}^{-1}$. The magnetic flux density $B$ is $2.5 \times 10^{-3}\,\text{T}$. The radius $r$ of the arc in the magnetic field is $4.5\,\text{cm}$. State your answer in $\text{C kg}^{-1}$.
The route of the negatively-charged particle before it enters the magnetic field is shown in Fig. 6.1. The magnetic field is directed into the plane of the paper. On Fig. 6.1, sketch the path of the particle in the magnetic field and after it leaves the field.
On Fig. 6.1, sketch the path of the particle in the magnetic field and after it leaves the field.