Two measurements are taken. $L = 6.8 \pm 0.1\,\text{cm}$ $T = 2.42 \pm 0.08\,\text{s}$ The relationship between $L$ and $T$ and $X$ is given by the equation below. $X = \frac{4\pi^2 L}{T^2}$ Calculate the value and uncertainty of $X$.
- A$45.8 \pm 0.2\,\text{cm s}^{-2}$
- B$45.8 \pm 0.3\,\text{cm s}^{-2}$
- C$46 \pm 2\,\text{cm s}^{-2}$
- D$46 \pm 4\,\text{cm s}^{-2}$