A steel ball is released and drops through a vertical distance $h$. The time $t$ for the drop is recorded using light gates. The data are shown in the table: $h = (4.05 \pm 0.01)\,\text{m}$, $t = (0.91 \pm 0.02)\,\text{s}$. The acceleration of free fall $g$ is determined from the equation shown below. $h = \frac{1}{2} g t^2$ What percentage uncertainty is there in the value of $g$?
- A$2.4\%$
- B$4.6\%$
- C$5.1\%$
- D$9.3\%$